16x^2+4x=6

Solution for 16x^2+4x=6 equation:

16x^2+4x=6

We move all terms to the left:

16x^2+4x-(6)=0

a = 16; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·16·(-6)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-20}{2*16}=\frac{-24}{32}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+20}{2*16}=\frac{16}{32}
=1/2
$